## Calculus, 10th Edition (Anton)

The graph of $y=f(g(x))$ is
According to the table, we have $$f(g(-3))=f(-1)=-2$$ $$f(g(-2))=f(0)=-1$$ $$f(g(-1))=f(1)=0$$ $$f(g(0))=f(2)=1$$ $$f(g(1))=f(3)=2$$ $$f(g(2))=f(-2)=-3$$ $$f(g(3))=f(-3)=-4.$$