Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.2 New Functions From Old - Exercises Set 0.2 - Page 25: 34

Answer

$f(g(x))= f(1/x)= x/(x^2+1)$ $Domain:x\ne0$ $g(f(x))= g(x/(1+x^2))=(1+x^2)/x$ $Domain: x\ne0$

Work Step by Step

$f(g(x))= f(1/x)= x/(x^2+1)$ $Domain:x\ne0$ $g(f(x))= g(x/(1+x^2))=(1+x^2)/x$ $Domain: x\ne0$
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