Calculus, 10th Edition (Anton)

Published by Wiley

Chapter 0 - Before Calculus - 0.1 Functions - Exercises Set 0.1: 22

False.

Work Step by Step

This statement is not necessarily true since $g(x)= \frac{1}{\sqrt{f(x)}}$ is not defined for $x$ for which $f(x) \le 0$. The domain of $g$ consists of all those real numbers $x$ for which $f(x)>0$.

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