Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.1 Functions - Exercises Set 0.1 - Page 13: 22



Work Step by Step

This statement is not necessarily true since $g(x)= \frac{1}{\sqrt{f(x)}}$ is not defined for $x$ for which $f(x) \le 0$. The domain of $g$ consists of all those real numbers $x$ for which $f(x)>0$.
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