Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.1 Functions - Exercises Set 0.1 - Page 13: 15


Yes. $$y=\sqrt{25-x^2}$$

Work Step by Step

Yes, it is a function since there exists no real number for which there are two distinct values of $y$. This graph is the positive section of the circle$$x^2+y^2=25 \quad \Rightarrow \quad y= \pm \sqrt{25-x^2},$$so the function representing this section is $$y=\sqrt{25-x^2}.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.