Answer
Ans. tanθ=√21/2 cosecθ=5/2
Work Step by Step
Given:-secθ=5/2
Secθ=H/B
Applying Pythagoras theorem in ∆PQR
Putting H=5 , B=2
$H^2=P^2+B^2$
P=√21
tanθ=P/B=√21/2 cosecθ=H/B=5/2
Ans.
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