Answer
Ans. Sinθ=3/√10 cosθ=1/√10
Work Step by Step
Given:-tanθ=3
We know that
tanθ=P/B
Applying Pythagoras theorem in ∆PQR
$H^2=P^2+B^2$
Putting P=3 B=1
we get H=√10
Sinθ=3/√10 cosθ=1/√10
Ans.
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Appendix B - Trigonometry Review - Exercise Set B - Page A24: 7
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