Answer
Ans. Cotθ=√15 secθ=4/√15
Work Step by Step
Given:-cosecθ=4
Cosecθ=H/P
Applying the Pythagoras theorem in ∆PQR
$H^2=B^2+P^2$
H=4 B=√15
Cotθ=√15 secθ=4/√15
Ans.
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