Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 9 - Review - True-False Quiz - Page 656: 2

Answer

$\bf True$.

Work Step by Step

$\bf True$. $f(x)=y=\frac{lnx}{x}$ $y'=\frac{1-lnx}{x^{2}}$ Now, $x^{2}y'+xy=x^{2}\frac{1-lnx}{x^{2}}+x\frac{lnx}{x}$ $=1-lnx+lnc$ $=1$
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