Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 6 - Section 6.2 - Volume - 6.2 Exercises - Page 456: 2

Answer

$A=\frac{8\pi}{3}$

Work Step by Step

Formula is $A= \int\pi(f(x)^{2})-g(x)^{2})dx$ a= 0, b=4 $f(x)=\sqrt x$ $g(x)=\frac{1}{2}x$ $A= \int\pi((\sqrt x)^{2}-(\frac{1}{2}x)^{2})dx$ $= \int\pi(x)-(\frac{x^2}{4}))dx$ $=\pi( \frac{x^2}{2}-\frac{x^3}{3*4})|4,0$ $=\frac{\pi*4^2}{2}-\frac{\pi*4^3}{12}-\frac{\pi*0^2}{2}-\frac{\pi*0^2}{12}$ $=\pi*8-\frac{\pi*64}{12}-0$ $=\pi*8-\frac{\pi*16}{3}$ due to common factor of 4 $=\frac{8\pi}{3}$
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