Answer
$\int_{1}^{3}(2e^x-1)~dx = 2e^3-2e-2$
Work Step by Step
We can evaluate the integral using properties of integrals:
$\int_{1}^{3}(2e^x-1)~dx$
$= \int_{1}^{3}2e^x~dx - \int_{1}^{3}1~dx$
$= 2\int_{1}^{3}e^x~dx - \int_{1}^{3}1~dx$
$= 2(e^3-e)-1(3-1)$
$= 2e^3-2e-2$
