Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 396: 53

Answer

$\int_{0}^{1}(5-6x^2)~dx = 3$

Work Step by Step

We can evaluate the integral using properties of integrals: $\int_{0}^{1}(5-6x^2)~dx$ $= \int_{0}^{1}5~dx - \int_{0}^{1}6x^2~dx$ $= \int_{0}^{1}5~dx - 6\int_{0}^{1}x^2~dx$ $= 5(1-0) -6(\frac{1}{3})$ $= 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.