Answer
$g(4) = 3$
$g'(4) = 0$
Work Step by Step
$g(x) = \int_{0}^{x}f(t)~dt$
Then we can say that $f = g'$
We can find $g(4)$. This value is the area under the graph of $f$ between the points $t=0$ and $t = 4$.
$g(4) = -1+1+2+1 = 3$
We can find $g'(4)$:
$g'(4) = f(4) = 0$
