Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Review - Exercises - Page 429: 26

Answer

$\arctan x + C$

Work Step by Step

$$\eqalign{ & \int {\frac{{dx}}{{{x^2} + 1}}} \cr & {\text{From the basic derivatives: }}\frac{d}{{dx}}\left[ {\arctan x} \right] = \frac{1}{{{x^2} + 1}},{\text{ then}} \cr & \int {\frac{{dx}}{{{x^2} + 1}}} = \arctan x + C \cr} $$
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