Answer
We can see a sketch of one possible graph below.
Work Step by Step
$f'(5) = 0$
The slope of the graph is zero at $x = 5$
There could be a local maximum or a local minimum at this point.
$f'(x) \lt 0$ if $x \lt 5$
The graph is decreasing on this interval.
$f'(x) \gt 0$ if $x \gt 5$
The graph is increasing on this interval.
$f''(2) = 0$ and $f''(8) = 0$
$x=2$ and $x=8$ are points of inflection.
$f''(x) \lt 0$ if $x \lt 2$ or $x \gt 8$
The graph is concave down on these intervals.
$f''(x) \gt 0$ if $2 \lt x \lt 8$
The graph is concave up on this interval.
$\lim\limits_{x \to \infty}f(x) = 3$
$\lim\limits_{x \to -\infty}f(x) = 3$
There is a horizontal asymptote at $y=3$
