Answer
We can see a sketch of one possible graph below.
Work Step by Step
$x=0$ is a vertical asymptote.
$f'(x) \gt 0$ if $x \lt -2$
The graph is increasing on the interval $(-\infty, -2)$
$f'(x) \lt 0$ if $x \gt -2, x \neq 0$
The graph is decreasing on the interval $(-2,0)\cup (0, \infty)$
$f''(x) \lt 0$ if $x \lt 0$
The graph is concave down on the interval $(-\infty, 0)$
$f''(x) \gt 0$ if $x \gt 0$
The graph is concave up on the interval $(0,\infty)$
