Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 4 - Review - Exercises - Page 365: 12

Answer

$\lim\limits_{x \to \pi^-}(x-\pi)~csc~x = -1$

Work Step by Step

$\lim\limits_{x \to \pi^-}(x-\pi)~csc~x = \lim\limits_{x \to \pi^-}\frac{x-\pi}{sin~x}= \frac{0}{0}$ We can use L'Hospital's Rule: $\lim\limits_{x \to \pi^-}\frac{x-\pi}{sin~x}$ $=\lim\limits_{x \to \pi^-}\frac{1}{cos~x}$ $=\frac{1}{-1}$ $= -1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.