Answer
$g'(t)=\frac{1}{2t\sqrt{1+\ln t}}$
Work Step by Step
$g(t)=\sqrt{1+\ln t}\\
g'(t)=\frac{1}{2\sqrt{1+\ln t}}\times\frac{1}{t}\\
g'(t)=\frac{1}{2t\sqrt{1+\ln t}}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Section 3.6 - Derivatives of Logarithmic Functions - 3.6 Exercises - Page 224: 10
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