Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 16 - Review - Concept Check - Page 1209: 2

Answer

See the explanation below.

Work Step by Step

a) A conservative field is known to be a vector field which is the gradient of a scalar function (also known as a scalar potential function). It does not depend on the path. Mathematically, it can be shown as: $\nabla f=F$ b) From part (a), we have $\nabla f=F$ Here, the potential function for a conservative vector field $F$ is a function $f$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.