Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Review - Exercises - Page 1033: 28

Answer

(a) $x+y+z=3$ (b) $\frac{x-1}{2}=\frac{y-1}{2}=\frac{z-1}{2}$

Work Step by Step

$xy+yz+zx=3 ; (1,1,1)$ (a) Equation for a tangent plane is given as: $z-1=-(x-1)-(y-1)$ $z-1=-x-1-y+1$ $x+y+z=3$ (b) $x+y+z=3$ Equation of normal line is: $\frac{x-1}{2}=\frac{y-1}{2}=\frac{z-1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.