Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 844: 9

Answer

$ \vec {AB}=\lt 3,1 \gt$

Work Step by Step

Find vector for $ \vec {AB}$ $ \vec {AB}=\lt x_2-x_1,y_2-y_1$ $ \vec {AB}=\lt 1-(-2),2-1 \gt$ $ \vec {AB}=\lt 3,1 \gt$ The equivalent representation starting at the origin is a vector from point $(0,0)$ to the point $\lt 3,1 \gt$.
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