Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 12 - Section 12.2 - Vectors - 12.2 Exercises - Page 844: 28

Answer

The angle between the vector $\langle8,6\rangle$ and the x axis is $\theta=36.87^\circ$.

Work Step by Step

In order to find the angle between the vector $\langle8,6\rangle$ and the x axis we can simply imagine a triangle with a base of $8$ and a height of $6$. As a result we can find $\theta$ with simple trigonometry. $\tan{\theta}=\frac{6}{8}=\frac{3}{4}\Rightarrow\theta=\arctan{\frac{3}{4}}\approx36.87^\circ$
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