Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.6 - Absolute Convergence and the Ratio and Root Tests - 11.6 Exercises - Page 778: 22

Answer

The series is absolutely convergent by root test.

Work Step by Step

$\sum_{n=1}^{\infty}a_{n}=\sum_{n=1}^{\infty}\frac{(-2)^n}{n^n}$ $|a_{n}|=\frac{2^n}{n^n}=(\frac{2}{n})^{n}$ $\lim\limits_{n \to \infty} \sqrt[n] |a_{n}|=\lim\limits_{n \to \infty} \sqrt[n] {(\frac{2}{n})^{n}}$ $=\lim\limits_{n \to \infty} {\frac{2}{n}}$ $=0\lt 1$ The series is absolutely convergent by root test.
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