Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 692: 23

Answer

$\theta=\frac{\pi}{3}$

Work Step by Step

$y=\sqrt {3}x $ Putting $y=r\sin\theta$ and $x=r\cos\theta$, we have $r\sin\theta=\sqrt {3}r\cos\theta$ $\implies \frac{\sin\theta}{\cos\theta}=\sqrt 3$ Or $\tan\theta=\sqrt 3$ $\implies \theta=\arctan (\sqrt 3)$ Or $\theta=\frac{\pi}{3}$
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