Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 692: 18

Answer

$y=\sqrt 3x$ This is a line with slope $\sqrt 3$ passing through (0,0).

Work Step by Step

$\theta=\frac{ \pi}{3}$ $tan\theta=tan\frac{ \pi}{3}$ $\frac{sin\theta}{cos\theta}=\sqrt 3$ $\frac{rsin\theta}{rcos\theta}=\sqrt 3$ To convert polar equation to Cartesian coordinates, we use the equations $rcos \theta=x$ and $rsin \theta=y$ $\frac{y}{x}=\sqrt 3$ Hence, $y=\sqrt 3x$ This is line with slope $\sqrt 3$.
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