Answer
$\frac{dy}{dx}=\frac{4-10t}{6t^2+3}$
Work Step by Step
Find $dx/dt$:
$\frac{dx}{dt}=6t^2+3$
Find $dy/dt$:
$\frac{dy}{dt}=4-10t$
Find $\frac{dy}{dx}$:
$\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{4-10t}{6t^2+3}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 10 - Section 10.2 - Calculus with Parametric Curves - 10.2 Exercises - Page 679: 1
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