Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 50

Answer

$(f∘g)(x) = \sqrt{1+\sqrt x}$

Work Step by Step

$g(x)$ = $\sqrt x$ $f(x)$ = $\sqrt {x+1}$ $(f∘g)(x)$ = $f(g(x))$ = $f(\sqrt x)$ = $\sqrt {1+\sqrt x}$
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