Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 47

Answer

$g(x)=\sqrt[3] x$ $f(x)=\frac{x}{1+x}$

Work Step by Step

Separating the function into two processes: 1. $g(x)=\sqrt[3] x$ 2. $f(g(x))=f(\sqrt[3] x)=\frac{\sqrt[3] x}{1+\sqrt[3] x}=\frac{g(x)}{1+g(x)}$ $f(x)=\frac{x}{1+x}$
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