Answer
$1^{10}+2^{10}+3^{10}+4^{10}+\cdots+n^{10}$
Work Step by Step
We expand the sigma notation by writing $i^{10}$ as $i$ increases from 1 to n:
$\displaystyle \sum_{i=1}^{n}i^{10}=1^{10}+2^{10}+3^{10}+4^{10}+\cdots+n^{10}$
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