Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

APPENDIX E - Sigma Notation - E Exercises - Page A 40: 28

Answer

$63.5$ or $\frac{127}{2}$

Work Step by Step

We expand and simplify the sum: $\displaystyle \sum_{i=-2}^{4}2^{3-i}$ $=2^{5}+2^{4}+2^{3}+2^{2}+2^{1}+2^{0}+2^{-1}$ $=32+16+8+4+2+1+0.5$ $=63.5$ or $\frac{127}{2}$
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