Answer
$y=\frac{1}{3} x+\frac{20}{3}$
Work Step by Step
First, we find the slope as follows
$$
m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-12}{4-16}=\frac{-4}{-12}=\frac{1}{3}
.$$
The point-slope form of a line is given as:
$$y-y_1=m(x-x_1)$$
We plug in the given point and slope and solve for $y$:
$$y-8=\frac{1}{3} (x-4)\Longrightarrow y=\frac{1}{3} x-\frac{4}{3} +8=\frac{1}{3} x+\frac{20}{3}
.$$
