Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.7 - Formulas - Exercises - Page 256: 43

Answer

$$ h=\frac{VP-7920 \pi}{2\pi } .$$

Work Step by Step

To solve the given equation for $h$, we multiply both sides by $P$ and then we follow the following steps $$ V=\frac{2\pi(3960+h)}{P}\Longrightarrow VP=2\pi(3960+h)\Longrightarrow VP=7920 \pi+2\pi h\\ \Longrightarrow 2\pi h=VP-7920 \pi\\ \Longrightarrow \frac{2\pi h}{2\pi }=\frac{VP-7920 \pi}{2\pi }\\ \Longrightarrow h=\frac{VP-7920 \pi}{2\pi } .$$
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