Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.7 - Formulas - Exercises - Page 256: 28

Answer

$$F=\frac{9}{5} C +32 .$$

Work Step by Step

To solve the given equation for $ F$, we multiply both sides by $\frac{9}{5}$ and then we simplify as follows: $$C= \frac{5}{9}(F-32) \Longrightarrow \frac{9}{5} C=\frac{9}{5} \frac{5}{9}(F-32) \Longrightarrow \frac{9}{5} C =F-32 \\ \Longrightarrow F=\frac{9}{5} C +32 .$$
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