Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.6 - Applications Involving Equations - Exercises - Page 251: 5

Answer

The answer is: $\$825$ to John, $\$1650$ to Maria and $\$2475$ to Betsy.

Work Step by Step

We assign the variables: x = John's money y = Maria's money z = Betsy's money Step 1: Find the equations that represent the problem. We know that $x + y + z = 4950$, because the addition of money given to each one has to equal the total amount of money. $x+y+z=4950$ ->Eq. 1 From " Maria receives twice as much as John", we get: $y=2x$ ->Eq. 2 From "Betsy receives three times as much as John", we get: $z=3x$ ->Eq. 3 Step 2: Solve the system of equations. Using the substitution method, -> Substitute Eq. 2 and Eq. 3 into Eq. 1 $x+2x+3x=4950$ $6x=4950$ $x=\frac{4950}{9}$ $x=825$ -> Substitute the value for x in Eq. 2 $y=2(825)$ $y=1650$ -> Substitute the value for x in Eq. 3 $z=3(825)$ $z=2475$ Step 3: The answer is $\$825$ to John, $\$1650$ to Maria and $\$2475$ to Betsy.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.