Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.6 - Applications Involving Equations - Exercises - Page 251: 3

Answer

164 fluorescent light fixtures and 92 incandescent light fixtures

Work Step by Step

Assign the variables: x = number of fluorescent light fixtures y = number of incandescent light fixtures $\textbf{Step 1:}$ Find the equations that represent the problem. We know $x+y=256$, because the addition of the fluorescent fixtures and the incandescent fixtures has to equal the total light fixtures. $x+y=256$ $\leftarrow$ Eq. 1 We can get the second equation from the wording in the problem. "The number of fluorescent light fixtures will be 20 fewer than twice the number of incandescent light fixtures." $x=2y-20$ $\leftarrow$ Eq. 2 $\textbf{Step 2:}$ Solve the system of equations. Using the substitution method, $x+y=256$ $2y-20+y=256$ $3y=256+20$ $3y=276$ $y=\frac{276}{3}$ $y=92$ Now solve for x $x+y=256$ $x+92=256$ $x=256-92$ $x=164$ $\textbf{Step 3:}$ The answer is 164 fluorescent light fixtures and 92 incandescent light fixtures.
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