## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 6 - Cumulative Review - Page 265: 30

#### Answer

Tthe length of the rectangle is $10 \ ft$ and the width is $\frac{1}{2} \cdot 10=5 \ ft$

#### Work Step by Step

Assume that the length of the rectangle is $x$; then its width will be $\frac{1}{2}x$, now we have $$Perimeter \ =2x+2\cdot \frac{1}{2}x =30\ ft$$ That is $$3x=30 \ ft \Longrightarrow x=10 \ ft$$ Hence the length of the rectangle is $10 \ ft$ and the width is $\frac{1}{2} \cdot 10=5 \ ft$

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