Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Cumulative Review - Page 265: 18

Answer

$$\frac{ 43 }{9 \ x y^2}.$$

Work Step by Step

We divide by the monomial as follows: $$\frac{215x^2y^3}{45x^3y^5}=\frac{5\cdot 43 }{5\cdot 9 \ x y^2}=\frac{ 43 }{9 \ x y^2}.$$ Note that we can not simplify any further, because "$9$" does not go into "$43$" evenly.
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