Answer
$$64\ p^{15}q^{21}r^{3}
.$$
Work Step by Step
By raising each factor to the power and multiplying the exponents, we have
$$(4p^5q^7r)^3=4^3p^{15}q^{21}r^{3}=64\ p^{15}q^{21}r^{3}
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.4 - Multiplication of Monomials - Exercise - Page 224: 48
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