## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 5 - Section 5.4 - Multiplication of Monomials - Exercise - Page 224: 47

#### Answer

$$-32\ h^{15}k^{30}m^{10} .$$

#### Work Step by Step

By raising each factor to the power and multiplying the exponents, we have $$(-2h^3k^6m^2)^5=(-2)^5h^{15}k^{30}m^{10}= -32\ h^{15}k^{30}m^{10} .$$

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