Answer
a. $\frac{1}{16}\ mi$
b. $\frac{1}{2}\cdot \frac{1}{16}\ mi = \frac{1}{32}\ mi.$
Work Step by Step
For the measurement $10\frac{3}{16}\ mi$, we have
a. The precision is $\frac{1}{16}\ mi$ because the last fraction $\frac{3}{16}$ has an accuracy of $\frac{1}{16}$.
b. The greatest possible error is one-half the precision:
$$\frac{1}{2}\cdot \frac{1}{16}\ mi = \frac{1}{32}\ mi.$$
