Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Review - Page 207: 15


a. $\frac{1}{8}\ in$ b. $\frac{1}{16}\ in.$

Work Step by Step

For the measurement $1\frac{5}{8}\ in$, we have a. The precision is $\frac{1}{8}\ in$ because the last fraction $\frac{5}{8}$ has $\frac{1}{8}$th accuracy. b. The greatest possible error is one-half the precision: $$\frac{1}{2}\cdot \frac{1}{8}\ in = \frac{1}{16}\ in.$$
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