Elementary Technical Mathematics

$$13.0 \ in^2.$$
The area of the figure consists of the area of a square and two rectangles as follows $$Area \ = 6\cdot 6 \ cm^2+3\cdot 12 \ cm^2 + 2\cdot 6 \ cm^2= 84\ cm^2.$$ Now, to convert to $in^2$, we have $1 \ in = 2.54 \ cm$ and hence $$84 \ cm^2=\frac{84}{2.54^2} \ in^2=13.0 \ in^2.$$