Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.7 - Metric and U.S. Conversion - Exercise - Page 155: 30

Answer

$$13.0 \ in^2.$$

Work Step by Step

The area of the figure consists of the area of a square and two rectangles as follows $$Area \ = 6\cdot 6 \ cm^2+3\cdot 12 \ cm^2 + 2\cdot 6 \ cm^2= 84\ cm^2.$$ Now, to convert to $in^2$, we have $1 \ in = 2.54 \ cm$ and hence $$84 \ cm^2=\frac{84}{2.54^2} \ in^2=13.0 \ in^2.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.