Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.7 - Metric and U.S. Conversion - Exercise - Page 155: 26

Answer

$$12.6\ m^2 .$$

Work Step by Step

Since $1 m=1.09 yd$, then we have $$15\ yd^2 =\frac{ 15}{1.09^2}\ m^2 = 12.6\ m^2 .$$
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