Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.5 - Time, Current, and Other Units - Exercise - Page 149: 29


$$0.175 \ mF.$$

Work Step by Step

Since 1 $\mu F$=$10^{-6}$ F and 1 $mF$= $10^{-3} F$, then 1$\mu F$=$10^{-3} mF$. So we have $$175\ \mu F= 175\times 10^{-3} \ mF=0.175 \ mF.$$
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