Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.5 - Time, Current, and Other Units - Exercise - Page 149: 28


$$15,000\ KV.$$

Work Step by Step

Since 1 MV=$10^6$ V and 1 KV= $10^3$ V, then 1 MV=$10^3$ KV. So we have $$15\ MV= 15\times 10^3 \ KV=15,000\ KV.$$
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