Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.4 - Volume and Area - Exercise - Page 147: 44


0.650 $m^3$

Work Step by Step

We use unit conversions to solve this problem: $650L=650L\times\frac{1000cm^3}{1L}\times(\frac{1m}{100cm})^3=650L\times\frac{1000cm^3}{1L}\times\frac{1m^3}{1,000,000cm^3}=\frac{650,000}{1,000,000}m^3=0.650m^3$
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