Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.3 - Mass and Weight - Exercise - Page 144: 44


18,000 $\mu g$

Work Step by Step

We use unit conversions to find the answer: $18mg=18mg\times\frac{1g}{1000mg}\times\frac{1,000,000\mu g}{1g}=\frac{18,000,000}{1000}\mu g=18,000\mu g$
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