Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.3 - Mass and Weight - Exercise - Page 144: 43



Work Step by Step

We use unit conversions to find the answer: $885\mu g=885\mu g\times\frac{1g}{1,000,000\mu g}\times\frac{1,000mg}{1g}=\frac{885,000}{1,000,000}mg=0.885mg$
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