Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 16 - Review: 15

Answer

225

Work Step by Step

Just as each digit of a standard Base 10 number has a place value that is a power of 10, each digit of a hexadecimal, or Base 16, number has a place value that is a power of 16. Reading right to left from the decimal, the exponent starts at 0 and increases by 1. $\underset\uparrow E\ \ \ \ \underset\uparrow1$ $16^1\ 16^0$ Multiply each digit by its corresponding place value, using standard Base 10 computations, and sum to get the converted Base 10 (decimal) value. Note that letters are used in hexadecimal notation for digits whose value is greater than 9. A=10, B=11, C=12, D=13, E=14 and F=15. $(14\times16^1)+(1\times16^0)=224+1=225$
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