Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.5 - Circles - Exercise - Page 410: 19


$A=3.98in^{2}$ $C=7.07in$

Work Step by Step

The area of the circle can be calculated with the formula $A=\frac{\pi*d^{2}}{4}$. where we have the diameter $d=2.25in$ Thus, we have the area: $A=\frac{\pi*(2.25in)^{2}}{4}=3.98in^{2}$ For the circumference, we use the circle circumference formula:$C=\pi*d$. where we have the same diameter: $d=2.25in$ Thus, we have the circumference: $C=\pi*2.25in=7.07in$
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