Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.1 - Angles and Polygons - Exercise - Page 388: 20


$$\angle 1= \angle 2=45^o.$$

Work Step by Step

Since $\angle 1, \angle 2$ are complementary, then $\angle 1+ \angle 2=90$. Assuming that $\angle 1= \angle 2$, then $$2\angle 1=90$$ that is $$\angle 1= \angle 2=45^o.$$
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